www.qprq.net > X+1/X+2+X+6/X+7=X+5/X+6+X+2/X+3 简便方法

X+1/X+2+X+6/X+7=X+5/X+6+X+2/X+3 简便方法

x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 1+1/(x+1)-1-1/(x+3)=1+1/x+5)-1-1/(x+7) 1/(x+1)+1/(x+7)=1/(x+5)+1/(x+3) (x+7+x+1)/(x^2+8x+7)=(x+3+x+5)/(x^2+8x+15) (2x+8)/(x^2+8x+7)=(2x+8)/(x^2+8x+15) (2x+8)(x^2+8x+15)=(2x+8)(x^2+8x+7) (2x+8)(x^...

解答如下

原方程可化为: 1 - 1/(x+2) + 1 - 1/(x+7)=1 - 1/(x+3) + 1 - 1/(x+6) 即有:1/(x+3) - 1/(x+2)=1/(x+7) - 1/(x+6) 左右两边分别通分得:-1/[(x+3)(x+2)]=-1/[(x+7)(x+6)] 则有:(x+3)(x+2)=(x+7)(x+6) x²+5x+6=x²+13x+42 移项整理得...

(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6) 1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6) -1/(x+2)-1/(x+7)=-1/(x+3)-1/(x+6) 1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6) 1/(x+2)-1/(x+3)=1/(x+6)-1/(x+7) (x+3-(x+2))/(x+2)(x+3)=(x+7-(x+6))/(x+6)(...

一样可以解出来。 (2x+9)/(x^2+9x+14)=(2x+9)/(x^2+9x+18) 移项提取公因式:(2x+9)[1/(x^2+9x+14)-1/(x^2+9x+18)]=0 则有2x+9=0 =>x=-9/2 或:1/(x^2+9x+14)-1/(x^2+9x+18)=0,通分后得:4/【(x^2+9x+14)*(x^2+9x+18)】=0 此方程无解(此处判断需...

解: 1+1/x+1-1-1/x-3=1+1/x+5-1- 1/x+7 1/x+1-1/x+3-1/x+5+1/x+7=0 ( x+3-x-1)/(x+1)(x+3)=(x+7-x-5)/(x+5)(x+7) ( x+1)(x+3)=(x+5)(x+7) x^2+4x+3=x^2+12x+35 8x=-32 x=-4

x+2分之x+1+x+7分之x+6=x+3分之x+2+x+6分之x+5 x+1/x+2 + x+6/x+7=x+2/x+3+ x+5/x+6 1-1/x+2 + 1- 1/x+7=1-1/x+3+ 1-1/x+6 1/x+2 + 1/x+7=1/x+3+ 1/x+6 (x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6) (2x+9)(x+2)(x+7)=(2x+9)(x+3)(x+6) (2x+9)(x^...

把括号后去掉得:x+2/x-1-x-4/x-3+x+6/x+5-x-8/x-7 =(x-x+x-x)+(2/x-4/x+6/x-8/x)+(-1-3+5-7) =0-4/x-6 =-4/x-6 请采纳,谢谢!

网站地图

All rights reserved Powered by www.qprq.net

copyright ©right 2010-2021。
www.qprq.net内容来自网络,如有侵犯请联系客服。zhit325@qq.com