www.qprq.net > X+1/X+2+X+6/X+7=X+5/X+6+X+2/X+3 简便方法

X+1/X+2+X+6/X+7=X+5/X+6+X+2/X+3 简便方法

解分式方程 (x+1)/(x+2)+(x+6/(x+7)=(x+5)/(x+6)+(x+2)/(x+3) 解:1--1/(x+2)+1--1/(x+7)=1--1/(x+6)+1--1/(x+3) 1/(x+6)--1/(x+7)=1/(x+2)--1/(x+3) [(x+7)--(x+6)]/[(x+6)(x+7)]=[(x+3)--(x+2)]/[(x+2)(x+3)] 1/[(x+6)(x+7)]=1/[(x+2)(x+3)] x...

x+1/x+2+x+6/x+7=x+2/x+3+x+5/x+6 1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6) 1/(x+6)-1/(x+7)=1/(x+2)-1/(x+3) 1/(x+6)(x+7)=1/(x+2)(x+3) (x+6)(x+7)=(x+2)(x+3) 13x+42=5x+6 8x=-36 x=-4.5 经检验x=-4.5是方程的根。

原方程可化为: 1 - 1/(x+2) + 1 - 1/(x+7)=1 - 1/(x+3) + 1 - 1/(x+6) 即有:1/(x+3) - 1/(x+2)=1/(x+7) - 1/(x+6) 左右两边分别通分得:-1/[(x+3)(x+2)]=-1/[(x+7)(x+6)] 则有:(x+3)(x+2)=(x+7)(x+6) x²+5x+6=x²+13x+42 移项整理得...

看不懂题啊你不打括号啊

x+6/x+7+x+1/x+2=x+2/x+3+x+5/x+6 解:[(x+7)-1]/(x+7)+[(x+2)-1]/(x+2)=[(x+3)-1]/(x+3)+[(x+6)-1]/(x+6) 即:1-1/(x+7)+1-1/(x+2)=1-1/(x+3)+1-1/(x+6) 化简,移项,得 1/(x+6)-1/(x+7)=1/(x+2)-1/(x+3) 方程两边同时通分,得 [(x+7)-(x+6)]/(...

x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 1+1/(x+1)-1-1/(x+3)=1+1/x+5)-1-1/(x+7) 1/(x+1)+1/(x+7)=1/(x+5)+1/(x+3) (x+7+x+1)/(x^2+8x+7)=(x+3+x+5)/(x^2+8x+15) (2x+8)/(x^2+8x+7)=(2x+8)/(x^2+8x+15) (2x+8)(x^2+8x+15)=(2x+8)(x^2+8x+7) (2x+8)(x^...

(x+1)/(x+2)+(x+6)/(x+7)=(x+2)/(x+3)+(x+5)/(x+6) 1-1/(x+2)+1-1/(x+7)=1-1/(x+3)+1-1/(x+6) -1/(x+2)-1/(x+7)=-1/(x+3)-1/(x+6) 1/(x+2)+1/(x+7)=1/(x+3)+1/(x+6) 1/(x+2)-1/(x+3)=1/(x+6)-1/(x+7) (x+3-(x+2))/(x+2)(x+3)=(x+7-(x+6))/(x+6)(...

首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0, 即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程 (x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(x+3+1)/(x+3) 即1+1/(x+1)+1+1/(x+7)=1+1/(x+5)+1+1/(x+3) 1/(x+1)+1/(x+7)=1/(x+5)+1/(x+3) 1/(x+1)-1/(x+3)=1...

解: 1+1/x+1-1-1/x-3=1+1/x+5-1- 1/x+7 1/x+1-1/x+3-1/x+5+1/x+7=0 ( x+3-x-1)/(x+1)(x+3)=(x+7-x-5)/(x+5)(x+7) ( x+1)(x+3)=(x+5)(x+7) x^2+4x+3=x^2+12x+35 8x=-32 x=-4

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